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IBM DB2 9 Family Fundamentals Sample Questions:

1. Which of the following privileges permits a user to update the comment on a sequence?

A) CONTROL
B) USAGE
C) UPDATE
D) ALTER

2. Which of the following statements allows BOB to revoke access to the SAMPLE database from user TOM?

A) REVOKE tom FROM CONNECT ON DATABASE BY USER bob
B) REVOKE CONNECT ON DATABASE FROM USER tom
C) REVOKE ACCESS ON DATABASE FROM USER bob
D) REVOKE tom FROM ACCESS ON DATABASE BY USER bob

3. Application A holds an Exclusive lock on table TAB1 and needs to acquire an Exclusive lock on table TAB2. Application B holds an Exclusive lock on table TAB2 and needs to acquire an Exclusive lock on table TAB1. If lock timeout is set to -1 and both applications are using the Read
Stability isolation level, which of the following will occur?

A) Application B will read the data in table TAB1 and see uncommitted changes made by Application A
B) Application B will read the copy of table TAB1 that was loaded into memory when Application A first read it
C) Application B will be placed in a lock-wait state until ApplicationA releases its lock
D) Applications A and B will cause a deadlock situation

4. Which of the following products is used to shred extensible markup language documents?

A) DB2 XML Extender
B) DB2 Text Extender
C) DB2 Spatial Extender
D) DB2 AVI Extender

5. Given the following two tables:
NAMES NAME NUMBER
Wayne Gretzky 99 Jaromir Jagr 68 Bobby Orr 4 Bobby Hull 23 Brett Hull 16 Mario Lemieux 66 Mark Messier 11 POINTS NAME POINTS
Wayne Gretzky 244 Jaromir Jagr 168 Bobby Orr 129 Brett Hull 121 Mario Lemieux 189 Joe Sakic 94
Which of the following statements will display the player name, number, and points for all players that have scored points?

A) SELECT p.name,n.number, p.points FROM names n LEFT OUTER JOIN points p ON n.name = p.name
B) SELECT p.name,n.number, p.points FROM names n RIGHT OUTER JOIN points p ON n.name = p.name
C) SELECT p.name,n.number, p.points FROM names n INNER JOIN points p ON n.name = p.name
D) SELECT p.name,n.number, p.points FROM names n FULL OUTER JOIN points p ON n.name = p.name

Solutions: